Question

Taman disekolah Bambang berbentuk persegi panjang dan lebar taman berturut turut (5x-2)m san (x+8) m. Jika keliling taman tersebut 60 m, luas taman adalah...
Tolong dibantu dan buat caranya ya....

Answer 1

Verified answer

Kelas 7 Matematika
Bab Persamaan Linear Satu Variabel

Keliling = 60
2 . (p + l) = 60
5x - 2 + x + 8 = 60/2
6x = 30 - 6
x = 24/6
x = 4

p = 5x - 2
p = 5 . 4 - 2
p = 18 m

l = x + 8
l = 4 + 8
l = 12 m

Luas = p . l
Luas = 216 m²

Answer 2

Verified answer

Mapel = Matematika
Bab = Persamaan Linear Satu Variabel
Kelas = 7 SMP

Diketahui
panjang = (5x - 2) m
lebar = (x + 8) m
Keliling = 60 m

K. Persegi = 2 (p +l)
60 m = 2 (5x - 2 + x + 8)
60/ 2 = 5x + x -2 + 8
30 m = 6x + 6
-6x = 6 -30
x = -24 / -6
x = 4

panjang
= (5x - 2) m
= 5.4 - 2 m
= 18 m

lebar
= (x + 8) m
= 4 + 8 m
= 12 m

Luas Taman = p x l
Luas Taman = 18 m x 12 m
Luas Taman = 216 m²

Semoga membantu :)