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--------- < 4
t - 2
3t
--------- - 4 < 0
t - 2
3t - 4(t - 2)
------------------ < 0
t - 2
8 - t
-------- < 0
t - 2
t - 8
-------- > 0
t - 2
t = 2
t = 8
+ + + - - - + + +
______(2)____(8)_____
Daerah tanda uji positif adalh penyelesaian
Jadi interval penyelesaian adalah x < 2 atau x > 8