suma podstaw pewnego trapezu wynosi 18cm. jego pole ma 117cm2.ile wynosi wysokość tego trapezu
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\[ P = \frac{1}{2}(a + b)h \]
\[ 117 = \frac{1}{2}(18)h \]
\[ 117 = 9h \]
\[ h = \frac{117}{9} \]
\[ h \approx 13 \, \text{cm} \]
Wysokość tego trapezu wynosi około 13 cm.