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a) √ 45 - √ 125 - √ 20 = √ 3² · 5 - √ 5² · 5 - √ 2² · 5
= 3 √ 5 - 5 √ 5 - 2 √ 5 = ( 3 - 5 - 2 ) √ 5 = - 4 √ 5
Si lo quieres en un solo radical
= - √ 4 ² · 5 = - √ 16 · 5 = - √ 80
d) √ 20 + √ 45 + 2 √ 125 = √ 2² ·5 + √ 3² · 5 + 2 √ 5² · 5
= 2 √ 5 + 3 √ 5 + 10 √ 5 = ( 2 + 3 + 10 ) √ 5 = 15 √ 5
En un solo radical
= √ 15² · 5 = √ 225 · 5 = √ 1125
Los otros dos tienen radicales no semejantes , no tengo manera de sumarlos