Question

Suma de fracción triple con diferente denominador
Porfa doy coronita

Answer 1

Respuesta:

:D

Explicación paso a paso:

A) [tex]\frac{3}{4} +\frac{2}{5} +\frac{1}{7} = \frac{105+56+20}{140} = \frac{181}{140}[/tex]

B) [tex]\frac{6}{10} +\frac{3}{7} +\frac{1}{2} =\frac{42+30+35}{70} =\frac{107}{70}[/tex]

C) [tex]\frac{5}{6} +\frac{2}{4} +\frac{7}{11} =\frac{55+33+42}{66} =\frac{130}{66} =\frac{65}{33}[/tex]

D) [tex]\frac{8}{3} +\frac{6}{6} +\frac{5}{9} =\frac{24+9+5}{9} =\frac{38}{9}[/tex]

E) [tex]\frac{1}{5} +\frac{4}{15} +\frac{6}{10} =\frac{6+8+18}{30} =\frac{32}{30} =\frac{16}{15}[/tex]

F) [tex]\frac{2}{4} +\frac{2}{6} +\frac{1}{8} =\frac{12+8+3}{24} =\frac{23}{24}[/tex]