Barisan aritmetika
[tex]un = a + (n - 1)b \\ u13 = 10 + (13 - 1)3 \\ u13 = 10 + (12)3 \\ u13 = 10 + 36 \\ u13 = 46[/tex]
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Un = a + (n - 1)b
a = suku pertama
b = beda
Maka :
Un = a + (n - 1)b
U13 = 10 + (13 - 1)(3)
U13 = 10 + (12)(3)
U13 = 10 + 36
U13 = 46.
Jadi, suku ke-13 pada barisan aritmatika tersebut adalah 46.
Semoga membantu.
Verified answer
Barisan aritmetika
[tex]un = a + (n - 1)b \\ u13 = 10 + (13 - 1)3 \\ u13 = 10 + (12)3 \\ u13 = 10 + 36 \\ u13 = 46[/tex]