suku ke 7 arematikaadalah 22 dan suku ke 12 adalah 37 tentukan jumplah 5 suku pertama deret tersebut
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Sn = n/2 {2a + (n - 1) b}
u7 = 22
u12 = 37
u7 + 5b = 37
22 + 5b = 37
5b = 15
b = 3
u7 = 22
a + 6b = 22
a + 18 = 22
a = 4
Sn = n/2 {2a + (n - 1) b}
[tex]\sf s_5 = \frac{5}{2}\{ 2(4) + (4)(3)\}[/tex]
[tex]\sf s_5 = \frac{5}{2}\{ 8+12\} = 50[/tex]
jumpah 5 suku pertama deret tersebut = 50