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U7 = a+(6)b = 26
U3 = a+(2)b = 14
Dikurangi!
4b = 12
b = 3
Subtitusikan b
a+2b = 14
a+2*3 = 14
a+6 = 14
a = 14-6
a = 8
U10 = 8 + ( 9 ) 3
U10 = 8+27
U10 = 35
U7 = a + 6b = 26 => kedua suku dikurangkan menjadi :
-4b = 12
b = 3
untuk mencari a, subtitusikan b ke U3, maka
a + 2b = 14
a + 2 x 3 = 14
a + 6 = 14
a = 14 - 6
a = 8
Maka,
U10 = a + (n-1) x b
U10 = 8 + (9-1) x 3
U10 = 8 + 24
U10 =32