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35°C = 9/5 x 35 + 32 = 95°F
35°C = 4/5 x 35 = 28°R
a. 35°C
b. 95°F
c. 28°R
T = 308⁰K
Ditanya
a) T⁰C...?
b) T⁰F...?
c) T⁰R...?
Jawab
a) 308 - 273 = 35⁰C
b) 9/5 (308-273) + 32 = 95⁰F
c) 4/5 (308-273) = 28⁰R