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-5a+3b=4 |x1| -5a + 3b = 4
_______________________ +
-7b = 14
b= -2
substitusi
a - 2(-2) = 2
a +4 = 2
a=2-4
a=-2
2. 5c-2d=4 |x1| --> 5c - 2d = 4
4c+d=11 |x2| -> 8c + 2d = 22
_________________________ +
13c=26
c=2
substitusi
5(2) -2d = 4 --> 10-2d=4 --> -2d = 4 - 10 --> d = -6/-2 = 3
a=2+2b
3b-5a=4
3b-5(2+2b)=4
3b-10-10b=4
3b-10b=4+10
-7b=14
b=-2
2). 4c+d=11
d= 11-4c
5c-2d=4
5c-2(11-4c)=4
5c-22+8c=4
5c+8c=4+22
13c=26
c=2
4c+d=11
4(2)+d=11
8+d=11
d=11-8
d=3