Question

Suatu titik Q(6,3) mengalami dilatasi terhadap pusat(3,-5). Jika faktor pengalinya -1, tentukan koordinat akhir titikQ.​

Answer 1

Verified answer

Materi : Transformasi Geometri

P( x,y ) => D[ Q(a,b),k ] => ( a + k[ x - a ] , b + k[ y - b ] )

Maka

Q( 6,3 ) => D[ (3,-5) , -1 ] => ( x' , y' )

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x' = a + k[ x - a ]

x' = 3 + (-1)[ 6 - 3 )

x' = 3 - 3

x' = 0

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y' = b + k[ y - b ]

y' = - 5 + (-1)[ 3 - {-5} ]

y' = - 5 - 8

y' = -13

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Maka Bayangan Titik Q( 6,3 ) setelah dilatasi terhadap titik pusat ( 3,-5 ) adalah Q'( 0,-13 ).

Semoga bisa membantu

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Answer 2

(x' , y') = (3 + (-1(6 - 3) , (-5 + (-1)(3 - (-5)

(x' , y') = (3 + (-1(3) , (-5 + (-1)(3 + 5)

(x' , y') = (3 - 3) , (-5 - 8)

(x' , y') = (0 , (-(5 + 8)

(x' , y') = (0 , -13)