sukU banyaksisa = nilai fungSI
Penjelasan dengan langkah-langkah:
Suatu suku banyak bila dibagi x + 4 mempunyai sisa -7, bila dibagi x + 1 mempunyai sisa 5. Hitunglah sisanya bila dibagi x² + 5x + 4!
f(x) dibagi (x² + 5x + 4) , sisa s(x) = ax + b
f(x) dibagi (x + 4)(x + 1) , sisa s(x) = ax + b
dibagi ( x + 4) , sisa - 7 ⇒ f(-4) = - 7
dibagi (x + 1 ), sisa 5 ·⇒ f(-1) = 5
f(-4) = - 7
f(-1) = 5 ( - )
-3a = - 12
a = 4
b = -7 + 4a
b = - 7+ 16
b = 9
sisa s(x ) = ax + b
s(x) = 4x+ 9
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sukU banyak
sisa = nilai fungSI
Penjelasan dengan langkah-langkah:
Suatu suku banyak bila dibagi x + 4 mempunyai sisa -7, bila dibagi x + 1 mempunyai sisa 5. Hitunglah sisanya bila dibagi x² + 5x + 4!
f(x) dibagi (x² + 5x + 4) , sisa s(x) = ax + b
f(x) dibagi (x + 4)(x + 1) , sisa s(x) = ax + b
dibagi ( x + 4) , sisa - 7 ⇒ f(-4) = - 7
dibagi (x + 1 ), sisa 5 ·⇒ f(-1) = 5
f(-4) = - 7
f(-1) = 5 ( - )
-3a = - 12
a = 4
f(-4) = - 7
b = -7 + 4a
b = - 7+ 16
b = 9
sisa s(x ) = ax + b
s(x) = 4x+ 9