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Misal dan 100 gram sampel.komponen penyusun zat :
O dengan persen massa = 90%
massa per 100g = 90 gram
Mol C = 90 / Ar C
mol C = 90/12 = 7,5
H dengan persen massa = 10%
massa per 100 g = 10 gram
Mol H = 10 / Ar H
mol H = 10/1 = 10
perbandingan mol C : H
= 7,5 : 10
= 3 : 4
jadi rumus empiris senyawanya adalah C3H4