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◾ Materi : Pegas◾ Sub materi : Pegas
◾ Mapel : Fisika
◾ Keyword : Pegas, Energi Potensial Pegas
Diketahui :
F1 = 5 N
Δx1 = 2 cm = 0,02 m
Ditanya :
Ek = ? -> F = 25 N
Penyelesaian :
*Cari konstanta pegas
F = k. Δx
5 = k. 0,02
k = 5/0,02
k = 250 N/m
*Cari pertambahan panjang pegas kedua
F = k. Δx
25 = 250. Δx
Δx = 0,1 m
*Cari energi potensial pegas
Ep = ½kΔx²
Ep = ½(250)(0,1)²
Ep = 1,25 J
Jadi, besarnya energi potensial pegas adalah 1,25 J
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-vin