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TERMODINAMIKA• Mesin Carnot
Keadaan pertama
η = 40 % = 0,4
T₁ = 400 K
T₂ = __?
η = 1 - T₂/T₁
0,4 = 1 - T₂/400
T₂/400 = 1 - 0,4
T₂/400 = 0,6
T₂ = 0,6 • 400
T₂ = 240 K
Keadaan kedua
T₁' = 640 K ← diubah
T₂ = 240 K ← tetap
η' = ___?
η' = 1 - T₂/T₁'
η' = 1 - 240/640
η' = 1 - ⅜
η' = ⅝ = 62,5 % ✔️