Suatu gas mempunyai volume X liter. jika kondisi gas tersebut Y Derajat Celcius, 114 cmHg, jumlah molgas tersebut adalah...(R=0,082)
AndreasWatang
*Persamaan gas ideal Diketahui : P = 114 cmHg = 114/76 atm = 1,5 atm V = X Liter R = 0,082 mol K / atm L T = Y°C = (Y+273)K Ditanya : n = .... ? Jawab : PV = nRT 1,5X = n . 0,082 . (Y+273) 18,29X = n(Y+273) n = (18.29X) / (Y+273)
Diketahui :
P = 114 cmHg = 114/76 atm = 1,5 atm
V = X Liter
R = 0,082 mol K / atm L
T = Y°C = (Y+273)K
Ditanya :
n = .... ?
Jawab :
PV = nRT
1,5X = n . 0,082 . (Y+273)
18,29X = n(Y+273)
n = (18.29X) / (Y+273)