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f(1) = -3
a(1)+b = -3
a+b = -3.....(1)
f(4) = 3
a(4) +b = 3
4a + b = 3.....(2)
dari pers (1)
a+b = -3 --->> a = -3 -b.....(3)
substitusikan pers (3) ke pers (2)
4a + b = 3
4(-3-b) +b =3
-12 -4b +b = 3
-4b + b = 3 +12 .....(-12 pindah ruas jd +12)
-3b = 15
b = 15 : -3
b = -5
dari pers (3)
a = -3-b
a = -3 -(-5)
a = -3 +5
a = 2
f(x) = ax +b, maka rumus f(x) = 2x -5
-3=a+b
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6=3a
a=2
3=4x2 +b
3=8+b
b=8-3
b=5
jadi rumus f(x)= 2x+5