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jika h(2)=18
jika h(-2)=-6
persamaan satu
h(2)=2a+3b=18
persamaan dua
h(-2)=-2a+3b=-6
eliminasi kan pers. 1 dan pers. 2
2a+3b=18
-2a+3b=-6
*dikurang utk mng eliminasi b
4a=24
a=6
substitusi kan
2a+3b=18
2(6)+3b=18
12+3b=18
3b=18-12
3b=6
b=2
maka nilai
2a-2b
2(6)-2(2)
=12-4
=8