Question

Suatu fungsi f:x -> x²+2 dg daerah asal {-2,-1,0,1,2}.Daerah hasil fungsi trsbut adlh...

Answer 1

F(x) = x² +2
f(-2) = (-2)² +2
       = 4 +2 = 6
f(-1) = x² +2
       = (-1)² +2
       = 1 +2 = 3
f(0) = 0² +2
       = 2
f(1) = 1² +2
       = 1 +2 = 3
f(2) = 2² +2
       = 4 +2 = 6
Jadi, daerah funsinya adalah = {2, 3, 6}.

Answer 2

F(x) = x²+2
f(-2) = (-2)²+2 = 6
f(-1) = (-1)²+2 = 3
f(0) = (0)²+2 = 2
f(1) = (1)²+2 = 3
f(2) = (2)²+2 = 6
jadi daerah hasilnya adalah: {2,3,6}