Suatu fungsi f :R ----- > R dengan ketentuan sebagai berikut F:x -----> x+2jika x ganjil F:x---- > x-1 jika x genap Dengan x variable pada R =(1,3,3,......7), tentukan fungsi f dalam bentuk himpunan pasangan berurutan !
DB45
F(x)= x+2 jika x ganjil f(x) = x -1 jika x genap X = 1,2,3,4,5,6,7 x =1 -> ganjil --> f(1) = 1+2 = 3 --> (1,3) x= 2--> genap --> f(2) = 2-1 =1 --> (2,1) x = 3-->ganjil --> f(3) = 3+2 = 5 --> (3,5) x = 4 -->genap --> f(4)= 4-1 = 3 --> (4,3) x = 5 -->ganjil --> f(5) = 5+2 =7 --> (5,7) x = 6--> genap--> f(6) = 6-1 =5 --> (6,5) x= 7--> ganjil--> f(7) = 7+2 = 9 --> (7,9)
f(x) = x -1 jika x genap
X = 1,2,3,4,5,6,7
x =1 -> ganjil --> f(1) = 1+2 = 3 --> (1,3)
x= 2--> genap --> f(2) = 2-1 =1 --> (2,1)
x = 3-->ganjil --> f(3) = 3+2 = 5 --> (3,5)
x = 4 -->genap --> f(4)= 4-1 = 3 --> (4,3)
x = 5 -->ganjil --> f(5) = 5+2 =7 --> (5,7)
x = 6--> genap--> f(6) = 6-1 =5 --> (6,5)
x= 7--> ganjil--> f(7) = 7+2 = 9 --> (7,9)
himp pasangan berurutan =
(1,3),(2,1),(3,5),(4,3),(5,7),(6,5),(7,9)