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f(-3)=11
11=-3a+b
f(1)=3
3=a+b
a+b=3
-3a+b=11 -
4a =-8
a=-2
a+b=3
(-2)+b=3
b=3+2
b=5
(D) -2 dan 5
f(-3)=11
f(x)=ax+b
1a+b=3
-3a+b=11
__________ -
4a=-8
a=-2
f(1)=3
2.1+b=3
2+b=3
b=3-2
b=1