Suatu fungsi f dinyatakan oleh f(x) = ax + b. Jika diketahui f(1) = 3 dan f(-3) = 11, nilai a dan b berturut-turut adalah .... A.4 dan -1 B.4 dan 7 C.-2 dan 1 D.-2 dan 5 PAKAI JALAN YAAA
mariani02021975
F(x) = ax + b f(1) = 3 f(x) = ax + b f(1) = a(1) + b = 3 = a + b = 3
f(-3) = 11 f(x) = ax + b f(-3) = a(-3) + b = 11 = -3a + b =11
= a + b = 3 -3a + b = 11 - 4a = -8 a = -8/4 a = -2
f(1) = 3
f(x) = ax + b
f(1) = a(1) + b = 3
= a + b = 3
f(-3) = 11
f(x) = ax + b
f(-3) = a(-3) + b = 11
= -3a + b =11
= a + b = 3
-3a + b = 11 -
4a = -8
a = -8/4
a = -2
= a + b = 3
-2 + b = 3
b = 3 + 2
b = 5
Jadi, jawabannya yaitu D -2 dan 5