Question

Suatu fungsi ditentukan dngn rumus f(x)=ax+b. jika f(3)=1 dan f(-2)=-9, maka nilai a dan b ber turut2 adalah?

Answer 1

F(x)=ax+b
 3a+b  = 1
-2a+b  = -9  -
5a=10
a=2

3.2+b=1
6+b=1
b=1-6= -5

a= 2
b= -5

Answer 2

F(x) = ax + b
f(3) = 3a + b
3a + b = 1

f(-2) = -2a + b
-2a + b = -9

3a + b = 1
b = 1 - 3a

-2a + b = -9
-2a + 1 - 3a = -9
-5a = -9 -1
-5a = -10
5a = 10
a = 10 /5
a = 2

3a + b = 1
3(2) + b = 1
6 + b = 1
b = 1 - 6
b = -5