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Verified answer
Pelajaran :MatematikaKelas :8
Bab :2
Nama Bab :Fungsi
Kode mapel:2
Kode :8.2.2
Jawab:
f(x)=ax+b
f(3)=a(3)+b
11=3a+b
b=11-3a
f(2)=a(2)+b
8=2a+(11-3a)
-a=8-11
a=3
b=11-3a
=11-3(3)
=11-9
=2
(a,b)=(3,2)
Verified answer
MAPEL = MATEMATIKAKELAS = 8
BAB = RELASI & FUNGSI
f(x) = ax + b = 11
f(3) = 3a + b = 11
f(x) = ax + b = 8
f(2) = 2a + b = 8
eliminasi nilai b
3a + b = 11
2a + b = 8
_________-
a = 3
subtitusi nilai a
3a + b = 11
3(3) + b = 11
9 + b = 11
b = 11 - 9
b = 2
a = 3
b = 2
rumus fungsi =
f(x) = ax + b
f(x) = 3x + 2