Question

Suatu fungsi dinyatakan dengan rumus f(x) =9-3x-x² dengan daerah asal {-2,-1,0,1,2} daerah hasil fungsi tersebut adalah?

Answer 1

9-(3(-2))-((-2)(-2))  = 9+6-4  =11
9-(3(-1))-((-1)(-1))  = 9+3-1 = 11
9-(3(0))-((0)(0))     = 9          = 9
9-(3(1))-((1)(1))     = 9-3-1   = 5
9-(3(2))-((2)(2))     = 9-6-4   = -1
Daerah hasil ={-1,5,9,11}

Answer 2

F(-2) = 9 - 3(-2) - (-2)²
f(-2) = 9 - (-6) - (-4)
f(-2) = 9 + 6 + 4 
f(-2) = 19


f(-1) = 9 - 3(-1) - (-1)²
f(-1) = 9 - (-3) - (-1)
f(-1) = 9 + 3 + 1
f(-1) = 13

f(0) = 9 - 3(0) - (0)²
f(0) = 9 - (0) - (0)
f(0) = 9 -0
f(0) = 9

f(1) = 9 - 3(1) - (1)²
f(1) = 9 - 3 - 1
f(1) = 5

f(2) = 9 - 3(2) - (2)²
f(2) = 9 - 6 - 4
f(2) = 3 - 4
f(2) = -1

Maaf kalo salah..