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f(-2) = -2a+b = 7
f(3) = 3a+b = -3
__________ -
-5a = 10
a = 10/-5
a = -2 -------> 3a+b = -3
3.(-2)+b = -3
-6+b = -3
b = -3+6
b = 3
jadi, nilai a = -2 , dan b = 3
f(-2) = ax+b
7 = -2a+b ...(1)
f(3) = ax+b
-3 = 3a+b ....(2)
#eliminasi (1) dan (2)
-2a+b=7
3a+b=-3 -
-5a=10
a=-2
#substitusi a = -2 ke (2)
3a+b = -3
3(-2)+b=-3
- 6 + b = -3
b = -3+6
b = 3
maka , a = -2 , b = 3