Question

Suatu basa m(OH)2 mempunyai ksp = 4.10^-12. Berapkah ph larutan jenuh basa tersebut

Answer 1

Ksp M(OH)2 = [M2+][OH-]^2
4 × 10^-12 = (s)(2s)^2
4 × 10^-12 = 4s^3
s^3 = 10^-12
s = 10^-4
[OH-] = 10^-4
pOH = -log[OH-]
pOH = -log(10^-4)
pOH = 4
pH = 14-4 = 10

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