Question

Suatu balok memiliki luas alas, kanan, dan depan berturutan 16cm2. 6cm2, dan 24cm2.volume balok adalah...,

Answer 1

Lalas =  16cm²
Lkanan = 6cm²
Ldepan = 24cm²

Lalas = p.l
Lkanan = l.t
Ldepan = p.t

p.l = 16cm²
l.t = 6cm²
p.t = 24cm²

p = 16/l
t = 6/l
p.t = 24cm²
16/l.6/l = 24cm²
96/l² = 24
l² = 96/24
l² = 4
l = √4
l=2cm

p.l = 16
p.2 = 16
p = 16/2
p = 8cm

p.t = 24
8.t = 24
t = 24/8
t = 3cm

volume balok = p.l.t
=8.3.2
=48cm³

Answer 2

=√16.6.24
=√8.2.3.2.12.2
=√4.2.2.3.2.3.4
=4.2.3.2
=48 CM kubik