x dm3----------------0,2mola
3H2 + N2 -> 2NH3
3*22,4=67,2dm3---2 mole x = 6,72 dm3 H2
y dm3-------0,2mola
22,4dm3--- 2 mole y= 2,24 dm3 N2
(nie wiem czy dobrze zrobiłam)
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x dm3----------------0,2mola
3H2 + N2 -> 2NH3
3*22,4=67,2dm3---2 mole x = 6,72 dm3 H2
y dm3-------0,2mola
3H2 + N2 -> 2NH3
22,4dm3--- 2 mole y= 2,24 dm3 N2
(nie wiem czy dobrze zrobiłam)