Question

\sqrt{9 ^{2x+4} } = \frac{1}{3} ^{-3x-3}
berapa nilai x ??

Answer 1

9^(2x + 4) = (1/3)^(-3x - 3)
3^(3(2x + 4)) = 3^(-1(-3x - 3)) ⇔ coret 3
3(2x + 4) = -1(-3x - 3)
6x + 12 = 3x + 3
6x - 3x = 3 - 12
3x = -9
x = -9/3
x = -3