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(k+1) = 2(a+1)
(k-6) = 3(a-6)
(1)
k+1 = 2a+2
k-2a = 1
(2)
k-6 = 3a-18
k - 3a = -12
eliminasi
k-2a=1
k-3a=-12 (dikurang)
didapat a=13 tahun
k-2(13)=1
k-26=1
k=27 tahun
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