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FISIKA ATOM• spektrum
deret Paschen n' = 3
λ = 1,28×10⁻⁶ m
n = ___?
1/λ = R (1 / n'² - 1 / n²)
1/1,28×10⁻⁶ = 1,097×10⁷ (1/3² - 1/n²)
0.0712 ≈ ⅑ - 1/n²
1/n² = ⅑ - 0,0712
1/n² ≈ 0,04
n² = 25
n = 5 ✔️