Question

Sp ye yg bc jwb prtnyaan sy... Berapakah titik didih dan titik beku larutan 0,1 mol Ba(NO3)2 dalam 500 gram air. kb air=0,52°C m-¹;ki air=1,86°C
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#yg bisa jwb,tp jgn asal2an y..

Answer 1

Titik didih,delta tb = 0.56 x 3x0.1 x2 = 0.336 Tb = 100.336 C Titik beku, delta to = 1.36 x 3 x 0.1 x 2 = 0,816 Tf = -0,816 C

Answer 2

Semoga membantu yaaaa


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