a) [tex]\frac{3}{2}-\frac{3}{4} = \frac{6-3}{4} = \frac{3}{4} \\[/tex]
b) [tex]\frac{1}{2} -\frac{1}{3} = \frac{3-2}{6} = \frac{1}{6}[/tex]
c) [tex]\frac{1}{3} - \frac{1}{4} = \frac{4-3}{12} = \frac{1}{12}[/tex]
g) [tex]2\frac{1}{4} - 1\frac{1}{3} = \frac{9}{4} - \frac{4}{3} = \frac{27-16}{12} = \frac{11}{12}[/tex]
e) [tex]\frac{5}{3} - \frac{3}{6} = \frac{10-3}{6} = \frac{7}{6}[/tex]
f) [tex]3\frac{1}{3} - 2\frac{1}{4} = \frac{10}{3} - \frac{9}{4} = \frac{40-27}{12} = \frac{13}{12}[/tex]
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Verified answer
a) [tex]\frac{3}{2}-\frac{3}{4} = \frac{6-3}{4} = \frac{3}{4} \\[/tex]
b) [tex]\frac{1}{2} -\frac{1}{3} = \frac{3-2}{6} = \frac{1}{6}[/tex]
c) [tex]\frac{1}{3} - \frac{1}{4} = \frac{4-3}{12} = \frac{1}{12}[/tex]
g) [tex]2\frac{1}{4} - 1\frac{1}{3} = \frac{9}{4} - \frac{4}{3} = \frac{27-16}{12} = \frac{11}{12}[/tex]
e) [tex]\frac{5}{3} - \frac{3}{6} = \frac{10-3}{6} = \frac{7}{6}[/tex]
f) [tex]3\frac{1}{3} - 2\frac{1}{4} = \frac{10}{3} - \frac{9}{4} = \frac{40-27}{12} = \frac{13}{12}[/tex]