Question

Solusi dari x persamaan (2x + 1)^2 = (x - 1)^2 + 3x( x + 2 ) adalah ?

^=pangkat

Answer 1

(2x+1)^2=(x-1)^2 + 3x (x+2)
= (2x+1)(2x+1) = (x-1)(x-1) + 3x (x+2)
= 4x^2 + 4x + 1 = x^2 - 2x + 1 +3x^2 +6x
= 4x^2 + 4x + 1 = 4x^2 + 4x +1

Answer 2

(2x+1)^2 = (x-1)^2 + 3x(x+2)
(2x+1)(2x+1) = {(x-1)(x-1)} + (3x^2+6x)
4x^2+2x + 2x+1 = (x^2-x-x+1) + (3x^2+6x)
4x^2+4x+1 = (x^2-2x+1) + (3x^2+6x)
4x^2+4x+1 = 3x^4+6x^3-6x^3+12x^2+3x^2+6x
4x^2+4x+1 = 3x^4+15x^2+6x
1 = 3x^4+15x^2-4x^2+6x-4x
1 = 3x^4+11x^2+3x

= 3x^4+11x^2+3x-1