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X. 50-x
Pitagoras
H=h
H²=A²+x²
h²=a²+(50-x)²
√(A²+x²) = √(a²+(50-x)²)
A²+x² = a² +(50-x)²
(30)²+x²= (20)²+(50-x)²
900+x²=400+2500-100x+x²
100x = 2000
X=20
La distancia q apareció el pez es a los 20 metros del tronco de la palmera mayor.