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m = 6 kg
F = 24 N
a = F/m
a = 24/6
a = 4 m/s²
d = v₀ t + (0,5) a t²
como esta inicialmente en reposo entonces
v₀ = 0 m/s
si t = 10 s entonces
d = (0)(10) + (0,5)(4)(10²)
d = 200 m
la distancia recorrida es de 200 m