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agan bisa penyelesaian??
mol NaOH = 0,1x40 = 4mmol
volume larutan = 250mL
Konsentrasi [OH] = jumlah mol/jumlah V
= 1+4/250
= 5/250
= 0,02 M (D)
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PV=nRT. kita pakai persamaan V/n = konstan
V1/n1 = V2/n2
massa gas O2 = 16 gram (D)