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dit. dy/dx=y'
u=x+5 -> u'=1
v=(2x+1)^5 ->v'=(2)(5(2x+1)^4)=10(2x+1)^4
*u=2x+1 -> u'=2
*v=u^5 -> v'=5u^4=5(2x+1)^4
y'=u'v+uv'
y'=(1)(2x+1)^5 + (x+5)(5(2x+1)^4
y'=(2x+1)^5 + (5x+25)(2x+1)^4
y'=(2x+1)^4[(2x+1)+(5x+25)]
y'=(2x+1)^4(7x+26)
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