Soal terlampir.Terakhir ;-;.... Question from @Rovy10

ikyel04

$\rm\angle{AOD} + \angle{BOC} = 110^{\circ}$

karena besar sudut AOD dan BOC sama, maka kita dapat mengganti BOC dengan AOD.

$\rm\angle{AOD} + \angle{AOD} = 110^{\circ}$

$2\rm\angle{AOD} = 110^{\circ}$

$\rm\angle{AOD} = \frac{110^{\circ}}{2}$

$\rm\angle{AOD} = 55^{\circ}$

Menentukan besar $\rm\angle{DOC}$

$\rm\angle{DOC}+\angle{AOD} = 180^{\circ}$

$\rm\angle{DOC}+55^{\circ}= 180^{\circ}$

$\rm\angle{DOC}= 180^{\circ}-55^{\circ}$

$\rm\angle{DOC}= 125^{\circ}$

opsi C

2 votes Thanks 6

jika ∠AOD + ∠BOC = 110° , maka besar ∠DOC adalah.....

jawab :

$< doc = \frac{36° - ( < aod + < boc)}{2}$

$< doc = \frac{360° - 110°}{2}$

$< doc = \frac{250°}{2}$

${ \boxed{ \mathfrak{ = 125°}}}$

jadi besar <DOC adalah 125° ( C )

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6 votes Thanks 12