Question

soal remedial matematika ​

Answer 1

Verified answer

Jawab:

1/3

Penjelasan dengan langkah-langkah:

Lim x² - 4 / x³ - 8

x→2

Lim (x - 2)(x + 2) / (x - 2)(x² + 2x + 4)

x→2

Lim (x + 2) / (x² + 2x + 4)

x→2

= (2 + 2) / (2² + 2(2) + 4)

= 4 / 4 + 4 + 4

= 4 / 12

= 1/3

Answer 2

Jawab:

1/3

Penjelasan dengan langkah-langkah:

[tex]\lim_{x \to \22} \frac{x^{2}-4 }{x^3-8}[/tex]

[tex]\lim_{x \to \22} \frac{x^2-2^2}{x^3-2^3}[/tex]

[tex]\lim_{x \to \22} \frac{(x-2)(x+2)}{(x-2)(x^2+2x+4}[/tex]

[tex]\lim_{x \to \22} \frac{x+2}{x^2+2x+4}[/tex]

[tex]\lim_{x \to \22} \frac{(2) + 2}{(2)^2+2(2)+4}[/tex]

[tex]\lim_{x \to \22} \frac{4}{4+4+4} =\frac{4}{12} =\frac{1}{3}[/tex]

Semoga membantu remedialnya ^-^