diketahui:
segitiga siku-siku ABC siku-siku di A dengan
AC = 4 cm
AB = 3 cm
segitiga siku-siku BCD siku-siku di B dengan
CD = 13 cm
ditanya:
Panjang BC ?
Panjang BD ?
Jawab :
BC² = AB² + AC²
BC² = 3² + 4²
BC² = 9 + 16
BC = √25
BC = 5
BD² = DC² - BC²
BD² = 13² - 5²
BD² = 169 - 25
BD = √144
BD = 12
Answered by BBO™
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diketahui:
segitiga siku-siku ABC siku-siku di A dengan
AC = 4 cm
AB = 3 cm
segitiga siku-siku BCD siku-siku di B dengan
CD = 13 cm
ditanya:
Panjang BC ?
Panjang BD ?
Jawab :
BC² = AB² + AC²
BC² = 3² + 4²
BC² = 9 + 16
BC = √25
BC = 5
BD² = DC² - BC²
BD² = 13² - 5²
BD² = 169 - 25
BD = √144
BD = 12
Answered by BBO™