#F
(8) f(x ) = |2x - 1| dan g(x) = |5 - x| , nilai f(3) - g(3) =
= |2x3 - 1| - |5 -3|
= |6 - 1| - |5 -3|
= |5| - |2|
= 5 - 2 = 3
(9) |x + 4| + | 5 - 2x| - |x - 2| , untuk x > 10
= +(x +4) + (- (5 - 2x)) - (+(x -2))
= x + 4 - 5 + 2x - x + 2
= 2x + 1
(10) |3x - 6| - |x - 4| |x + 1| untuk 2 < x< 4
= +(3x - 6) - ( -(x - 4)(x+ 1))
= 3x - 6 + (x - 4)(x + 1)
= 3x - 6 + x² - 3x - 4
= x² -10
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#F
(8) f(x ) = |2x - 1| dan g(x) = |5 - x| , nilai f(3) - g(3) =
= |2x3 - 1| - |5 -3|
= |6 - 1| - |5 -3|
= |5| - |2|
= 5 - 2 = 3
(9) |x + 4| + | 5 - 2x| - |x - 2| , untuk x > 10
= +(x +4) + (- (5 - 2x)) - (+(x -2))
= x + 4 - 5 + 2x - x + 2
= 2x + 1
(10) |3x - 6| - |x - 4| |x + 1| untuk 2 < x< 4
= +(3x - 6) - ( -(x - 4)(x+ 1))
= 3x - 6 + (x - 4)(x + 1)
= 3x - 6 + x² - 3x - 4
= x² -10