Question

Soal integral. Saya mohon bantuannya dengan cara. Trims sebelumnya.

Answer 1

∫ x². e⁻²ˣ dx

x² .....e⁻²ˣ
2x...(-1/2) e⁻²ˣ
2....(-1/2)(-1/2) e⁻²ˣ
0...(-1/2)(-1/2)(-1/2) e⁻²ˣ

= -1/2 x² e⁻ˣ - 1/2x e⁻²ˣ  - 1/4 e⁻²ˣ + c
= - 1/4 e⁻²ˣ (2x² - 2x +1) + c