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ΣE + ΣIR = 0
(- E₁ + E₂) + I (R₁ + R₂ + R₃ + R₄) = 0
(- 12 + 3) + I (2 + 2 + 3 + 3) = 0
- 9 + 10I = 0
10I = 9
I = 0,9 Ampere
Karena tidak ada percabangan maka semua arus pada resistor sama
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