Jawaban:
u3 = 30 <=> 30 = a + 2b
u6 = 51 <=> 51 = a + 5b
a + 5b = 51
a + 2b = 30
--------------- -
3b = 21
b = 7
diketahui beda = 7
suku pertama ??
30 = a + 2b
30 = a + 14
a = 30 - 14
a = 16
u15 = a + 14b
u15 = 16 + 14(7)
u15 = 114
\begin{gathered}s15 = \frac{15}{2} ( 16 + 114 ) \\ s15 = \frac{(15)(130)}{(2)} = 975\end{gathered}s15=215(16+114)s15=(2)(15)(130)=975
Penjelasan dengan langkah-langkah:
semoga mebantu
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Jawaban:
u3 = 30 <=> 30 = a + 2b
u6 = 51 <=> 51 = a + 5b
a + 5b = 51
a + 2b = 30
--------------- -
3b = 21
b = 7
diketahui beda = 7
suku pertama ??
30 = a + 2b
30 = a + 14
a = 30 - 14
a = 16
u15 = a + 14b
u15 = 16 + 14(7)
u15 = 114
\begin{gathered}s15 = \frac{15}{2} ( 16 + 114 ) \\ s15 = \frac{(15)(130)}{(2)} = 975\end{gathered}s15=215(16+114)s15=(2)(15)(130)=975
Penjelasan dengan langkah-langkah:
semoga mebantu