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Verified answer
√x + 4√y = 6 |x2| 2√x + 8√y = 122√x - √y = 3 |x1| 2√x - √y = 3
------------------------- (-)
9√y = 9
√y = 1
subtitusikan nilai √y = 1 ke 2√x - √y = 3
2√x - 1 = 3
2√x = 4
√x = 2
jadi
√y = 1
y = 1
√x = 2
x = 4
================================================
²log x + ³log y = 4
²log x⁴ + ³log y³ = 13
misalkan
m = ²log x dan n = ³log y, maka bentuk pers. menjadi
m + n = 4 |x4| 4m + 4n = 16
4m + 5n = 13 |x1| 4m + 5n = 13
----------------------- (-)
n = -3
m + n = 4
m - 3 = 4
m = 7
jadi
²log x = 7 → x = 2⁷
³log y = -3 → y = 1/3³