Jawab:
E
Penjelasan dengan langkah-langkah:
f(1) = 0
2 + b - 1 - 6 = 0
b = 5
f(x) = 2x^3 + 5x^2 - x - 6
f(x) = (x-1)(ax^2 + bx+c)
a = 2
c = 6
-a + b = 5
b = 7
f(x) = (x-1)(2x^2 + 7x + 6)
f(x) = (x-1)(2x+3)(x+2)
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Jawab:
E
Penjelasan dengan langkah-langkah:
f(1) = 0
2 + b - 1 - 6 = 0
b = 5
f(x) = 2x^3 + 5x^2 - x - 6
f(x) = (x-1)(ax^2 + bx+c)
a = 2
c = 6
-a + b = 5
b = 7
f(x) = (x-1)(2x^2 + 7x + 6)
f(x) = (x-1)(2x+3)(x+2)