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S₂ = 15
a + ar = 15
Maka,
S₄ = 255
a + ar + ar² + ar³ = 255
(a+ar) + r²(a+ar) = 255
15 + 15r² = 255
15r² - 240 = 0
r² - 16 = 0
(r+4)(r-4) = 0
Diminta geometri naik,
r = 4.
Sehingga:
a + ar = 15
a + 4a = 15
5a = 15
a = 3
Jadi,
a = 3, dan r = 4