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m H - 1 u - masa atomu wodoru
m P - 31 u - masa atomowa fosforu
m O - 16 u - masa atomowa tlenu
m H3PO4 = 3*1+31+4*16 = 3 + 31 + 64 = 98
% P = 31/98 ≈ 31,63%
mH3PO4=3*1u+31u+4*16u=98u
31u-x%
98u-100%
x=31u*100%/98u
x=31,63%P